# Copyright 2009 mwta committers

#

# Licensed under the Apache License, Version 2.0 (the "License");

# you may not use this file except in compliance with the License.

# You may obtain a copy of the License at

#

#     http://www.apache.org/licenses/LICENSE-2.0

#

# Unless required by applicable law or agreed to in writing, software

# distributed under the License is distributed on an "AS IS" BASIS,

# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.

# See the License for the specific language governing permissions and

# limitations under the License



""" Markup Example 05



Displaying the HTTP response headers for xHTML

(Includes the code from markup example 04)

"""



import urllib

request = urllib.FancyURLopener()

request.addheader('Accept', 'application/xhtml+xml') 

response = request.open("http://www.google.co.uk/m")

content = response.read() 

print response.info()