/pypy/module/crypt/interp_crypt.py
https://bitbucket.org/pypy/pypy/ · Python · 24 lines · 22 code · 2 blank · 0 comment · 3 complexity · 2ccdb5c7293d7713abc0d68e94ac365f MD5 · raw file
- from pypy.interpreter.gateway import unwrap_spec
- from rpython.rtyper.lltypesystem import rffi
- from rpython.translator.tool.cbuild import ExternalCompilationInfo
- import sys
- if sys.platform.startswith('darwin'):
- eci = ExternalCompilationInfo()
- else:
- eci = ExternalCompilationInfo(libraries=['crypt'])
- c_crypt = rffi.llexternal('crypt', [rffi.CCHARP, rffi.CCHARP], rffi.CCHARP,
- compilation_info=eci, releasegil=False)
- @unwrap_spec(word=str, salt=str)
- def crypt(space, word, salt):
- """word will usually be a user's password. salt is a 2-character string
- which will be used to select one of 4096 variations of DES. The characters
- in salt must be either ".", "/", or an alphanumeric character. Returns
- the hashed password as a string, which will be composed of characters from
- the same alphabet as the salt."""
- res = c_crypt(word, salt)
- if not res:
- return space.w_None
- str_res = rffi.charp2str(res)
- return space.wrap(str_res)