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/contrib/cvs/mdate-sh

https://bitbucket.org/freebsd/freebsd-head/
Shell | 92 lines | 57 code | 6 blank | 29 comment | 2 complexity | 550d1702af921bf66384638bb9333913 MD5 | raw file
 1#!/bin/sh
 2# Get modification time of a file or directory and pretty-print it.
 3# Copyright 1995, 1996, 1997 Free Software Foundation, Inc.
 4# written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
 5#
 6# This program is free software; you can redistribute it and/or modify
 7# it under the terms of the GNU General Public License as published by
 8# the Free Software Foundation; either version 2, or (at your option)
 9# any later version.
10#
11# This program is distributed in the hope that it will be useful,
12# but WITHOUT ANY WARRANTY; without even the implied warranty of
13# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
14# GNU General Public License for more details.
15#
16# You should have received a copy of the GNU General Public License
17# along with this program; if not, write to the Free Software Foundation,
18# Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
19
20# Prevent date giving response in another language.
21LANG=C
22export LANG
23LC_ALL=C
24export LC_ALL
25LC_TIME=C
26export LC_TIME
27
28# Get the extended ls output of the file or directory.
29# On HPUX /bin/sh, "set" interprets "-rw-r--r--" as options, so the "x" below.
30if ls -L /dev/null 1>/dev/null 2>&1; then
31  set - x`ls -L -l -d $1`
32else
33  set - x`ls -l -d $1`
34fi
35# The month is at least the fourth argument
36# (3 shifts here, the next inside the loop).
37shift
38shift
39shift
40
41# Find the month.  Next argument is day, followed by the year or time.
42month=
43until test $month
44do
45  shift
46  case $1 in
47    Jan) month=January; nummonth=1;;
48    Feb) month=February; nummonth=2;;
49    Mar) month=March; nummonth=3;;
50    Apr) month=April; nummonth=4;;
51    May) month=May; nummonth=5;;
52    Jun) month=June; nummonth=6;;
53    Jul) month=July; nummonth=7;;
54    Aug) month=August; nummonth=8;;
55    Sep) month=September; nummonth=9;;
56    Oct) month=October; nummonth=10;;
57    Nov) month=November; nummonth=11;;
58    Dec) month=December; nummonth=12;;
59  esac
60done
61
62day=$2
63
64# Here we have to deal with the problem that the ls output gives either
65# the time of day or the year.
66case $3 in
67  *:*) set `date`; eval year=\$$#
68       case $2 in
69	 Jan) nummonthtod=1;;
70	 Feb) nummonthtod=2;;
71	 Mar) nummonthtod=3;;
72	 Apr) nummonthtod=4;;
73	 May) nummonthtod=5;;
74	 Jun) nummonthtod=6;;
75	 Jul) nummonthtod=7;;
76	 Aug) nummonthtod=8;;
77	 Sep) nummonthtod=9;;
78	 Oct) nummonthtod=10;;
79	 Nov) nummonthtod=11;;
80	 Dec) nummonthtod=12;;
81       esac
82       # For the first six month of the year the time notation can also
83       # be used for files modified in the last year.
84       if (expr $nummonth \> $nummonthtod) > /dev/null;
85       then
86	 year=`expr $year - 1`
87       fi;;
88  *) year=$3;;
89esac
90
91# The result.
92echo $day $month $year