/contest/Tmt514BeverageCup/tmt201505 - E/testC.cpp

https://gitlab.com/mrfathin/UVa · C++ · 125 lines · 114 code · 10 blank · 1 comment · 21 complexity · e206bf751661cc94d1c3222fd3cdb122 MD5 · raw file

  1. //program C
  2. #include<iostream>
  3. #include<cstdio>
  4. #include<cstdlib>
  5. #include<cstring>
  6. #include<algorithm>
  7. #include<cmath>
  8. #include<vector>
  9. #include<set>
  10. #include<queue>
  11. #include<bitset>
  12. #include<ctime>
  13. using namespace std;
  14. struct point
  15. {
  16. long long x,y;
  17. int num;
  18. };
  19. int get()
  20. {
  21. char c;
  22. while(c=getchar(),(c<'0'||c>'9')&&(c!='-'));
  23. bool flag=(c=='-');
  24. if(flag)
  25. c=getchar();
  26. int x=0;
  27. while(c>='0'&&c<='9')
  28. {
  29. x=x*10+c-48;
  30. c=getchar();
  31. }
  32. return flag?-x:x;
  33. }
  34. void output(int x)
  35. {
  36. if(x<0)
  37. {
  38. putchar('-');
  39. x=-x;
  40. }
  41. int len=0,data[10];
  42. while(x)
  43. {
  44. data[len++]=x%10;
  45. x/=10;
  46. }
  47. if(!len)
  48. data[len++]=0;
  49. while(len--)
  50. putchar(data[len]+48);
  51. putchar('\n');
  52. }
  53. point p[6000],q[6000];
  54. long long operator *(point a,point b)
  55. {
  56. return a.x*b.y-a.y*b.x;
  57. }
  58. int zone(point a)
  59. {
  60. if(a.x>0&&a.y>=0)
  61. return 0;
  62. if(a.y>0&&a.x<=0)
  63. return 1;
  64. if(a.x<0&&a.y<=0)
  65. return 2;
  66. return 3;
  67. }
  68. bool operator <(point a,point b)
  69. {
  70. int p=zone(a),q=zone(b);
  71. if(p!=q)
  72. return p<q;
  73. return a*b>0;
  74. }
  75. int main()
  76. {
  77. int totaltest=get();
  78. for(int test=1;test<=totaltest;test++)
  79. {
  80. int n=get();
  81. for(int i=0;i<n;i++)
  82. {
  83. p[i].x=get();
  84. p[i].y=get();
  85. p[i].num=i;
  86. }
  87. printf("Case #%d:\n",test);
  88. for(int i=0;i<n;i++)
  89. {
  90. for(int j=1;j<n;j++)
  91. if(p[j].num==i)
  92. swap(p[j],p[0]);
  93. int m=n-1;
  94. for(int j=0;j<m;j++)
  95. {
  96. q[j].x=p[j+1].x-p[0].x;
  97. q[j].y=p[j+1].y-p[0].y;
  98. }
  99. sort(q,q+m);
  100. for(int j=0;j<m;j++)
  101. q[m+j]=q[j];
  102. int ans=n;
  103. for(int l=0,r=0;l<m;l++)
  104. {
  105. while(r<l+m&&q[l]*q[r]>=0)
  106. r++;
  107. ans=min(ans,m-(r-l));
  108. }
  109. if(n<=2)
  110. ans=0;
  111. output(ans);
  112. }
  113. }
  114. return 0;
  115. }